[Netwhat] 연습문제 정리

Netwhat 문제를 통해 네트워크 개념을 복습했다.

문제 출처

adblanc/netwhat42-train 365kim/42_cursus/2_netwhat

유용한 링크

10진수 <-> 2진수 변환기 IP주소 범위 계산기 서브넷마스크 Reference Table

1. IP adress

선행지식

1.1. IP주소 크기 구하기

Q. What is the size of an IPv4 address?

- 128 bits
- 32 bits 
- 64 miles
- 16 bits
- 8 bits
- 64 bytes
- 128 bytes


Answer : 32 bit

Q. What is the size of an IPv6 address?

- 128 bits
- 32 bits 
- 64 miles
- 16 bits
- 8 bits
- 64 bytes
- 128 bytes


Answer : 128 bit

Q. To the test IP stack on your local host, which IP address would you ping?

- 127.0.0.0
- 1.0.0.127
- 127.0.0.1
- 127.0.0.255


Answer : 127.0.0.1

1.2. IP주소 클래스 구하기

Q. What is the default IP address class available?

- A AND B
- FIRST
- C
- B


Answer : C

Q. Which IP address class has more host addresses available by default?

- C
- D
- E
- F
- FIRST(A)


Answer : FIRST(A)

Q. Which of this is not a class of IP address?

- Class D
- Class F
- Class C
- Class E


Answer : Class F

2. Subnetting

선행지식

2.1 서브넷마스크 표기법

Q. What is the CIDR notation of the 255.255.128.0 subnet mask?

- /8
- /16
- /9
- /17


Answer : /17

Q. What is the CIDR notation of the 255.255.192.0 subnet mask?

- /5
- /31
- /18
- /14


Answer : /18

Q. What is the subnet mask of /24?

- 255.255.255.255
- 255.255.255.0
- 255.0.0.0
- 255.255.128.0
- 255.192.0.0
- 255.224.0.0


Answer : 255.255.255.0

2.2. 네트워크/브로드캐스트 주소 구하기

Q. What is the network address of a host with an IP address of 182.161.121.118/24?

- 180.0.0.0
- 182.161.121.64
- 182.161.120.0
- 182.161.121.116
- 0.0.0.0
- 182.161.96.0
- 182.160.0.0
- 182.161.121.0


Answer : 182.161.121.0
Solution : (182.161.121.118) & (255.255.255.0) = 182.161.121.0

Q. What is the network address of a host with an IP address of 107.212.146.212/25?

- 107.212.146.208
- 107.128.0.0
- 0.0.0.0
- 64.0.0.0
- 107.212.128.0
- 107.212.146.128
- 107.212.0.0
- 107.208.0.0
- 107.212.146.192


Answer : 107.212.146.128
Solution : (107.212.146.212) & (255.255.255.128) = 107.212.146.128

Q. What is the network address of a host with an IP address of 166.175.144.121/23?

- 166.128.0.0
- 166.175.144.0
- 166.175.144.96
- 128.0.0.0
- 166.174.0.0
- 166.0.0.0
- 166.0.0.0
- 166.175.144.120


Answer : 166.175.144.0
Solution : (166.175.144.121) & (255.255.254.0) = 166.175.144.0

Q. What is the network address of a host with an IP address of 116.45.224.50/8?

- 116.0.1.0
- 116.0.0.0
- 116.255.255.0
- 116.255.255.255


Answer : 116.0.0.0
Solution : (116.45.224.50) & (255.0.0.0) = 116.0.0.0

Q. What is the network address of a host with an IP address of 45.195.37.187/16?

- 45.194.37.187
- 45.0.0.0
- 45.194.0.0
- 45.195.0.0


Answer : 45.195.0.0
Solution : (45.195.37.187) & (255.255.0.0) = 45.195.0.0

Q. What is the broadcast address of a host with an IP address of 51.254.122.100/24?

- 51.254.122.0
- 51.254.122.1
- 51.254.122.254
- 51.254.122.255

Answer : 51.254.122.255

2.3. 호스트 주소 수 구하기

Q. What is the maximum number of IP addresses that can be assigned to hosts on a local subnet using the 255.255.255.128 subnet mask?

- 128
- 60
- 126
- 62
- 252
- 258
- 124
- 58
- 64


Answer : 126
Solution : 2^(32 - 25) - 2 = 128 - 2 = 126

Q. What is the maximum number of IP addresses that can be assigned to hosts on a local subnet using the 255.224.0.0 subnet mask?

- 4194306
- 4194302
- 1048578
- 4194300
- 2097148
- 4194298
- 1048574
- 2097150
- 1048576


Answer : 2097150
Solution : 2^(32 - 11) - 2 = 2097152 - 2 = 2097150

Q. You have an interface on a router with the IP address of 124.144.156.248/21. Including the router interface, how many hosts can have IP addresses on the local network connected to the router interface?

- 1020
- 2050
- 2044    
- 4090
- 2046
- 2048
- 4092
- 2042
- 4094


Answer : 2046
Solution : 2^(32 - 21) - 2 = 2048 - 2 = 2046

Q. You have an interface on a router with the IP address of 240.19.3.205/12. Including the router interface, how many hosts can have IP addresses on the local network connected to the router interface?

- 1048576
- 2097154
- 1048574
- 524284
- 1048578
- 2097148
- 1048572


Answer : 1048574
Solution : 2^(32 - 12) - 2 = 1048576 - 2 = 1048574

2.4. 호스트주소 범위 구하기

Q. Which of the following proposals is the valid host range for the subnet on which the IP address 158.167.18.156/15 resides?

- 158.166.0.1- 158.167.255.253
- 158.165.255.253- 158.167.255.254
- 158.166.0.1- 158.167.255.254
- 158.166.0.2- 158.168.0.2


Answer : 158.166.0.1- 158.167.255.254
Solution : (Network)158.166.0.0 (Broadcast) 158.167.255.255

Q. Which of the following proposals is the valid host range for the subnet on which the IP address 1.93.149.6/17 resides?

- 1.93.127.255- 1.93.255.250
- 1.93.128.1- 1.94.0.1
- 1.93.128.1- 1.93.255.251
- 1.93.128.1- 1.93.255.254
- 1.93.128.1- 1.94.0.3


Answer : 1.93.128.1- 1.93.255.254
Solution : (Network)1.93.128.0 (Broadcast) 1.93.255.255

3. Public/Private IP address

선행지식

3.1. 사설 IP주소 고르기

Q. Which of the following IP addresses is a private address?

- 169.153.119.123
- 24.23.102.151
- 255.62.136.173
- 10.166.25.20
- 46.244.138.171
- 27.147.158.251


Answer : 10.166.25.20

Q. Which of the following IP addresses is a private address?

- 222.9.230.144
- 135.167.134.35
- 172.32.0.5
- 27.157.141.96
- 172.16.0.2
- 129.244.78.149
- 137.223.167.235


Answer : 172.16.0.2

Q. Which of the following IP addresses is a private address?

- 108.246.233.231
- 146.227.105.173
- 59.155.254.18
- 253.29.133.220
- 192.168.20.253
- 94.152.104.99


Answer : 192.168.20.253

4. Transport Layer

선행지식

4.1. TCP/UDP 특징

Q. Which of the following propositions is not true?

- UDP is faster, simpler and more efficient than TCP
- UDP only has the basic error control mechanism
- UDP is a datagram oriented protocol
- UDP does not support broadcasting


Answer : UDP does not support broadcasting

Q. Which of the following propositions is not true?

- TCP is a connection-oriented protocol
- TCP does not support broadcasting
- TCP provides extended error checking mechanisms, because it provides flow control and data acknowledgement
- Data sequencing is a TCP feature (this means that packets arrive in order in the recipient)
- The delivery of data to the destination cannot be guaranteed in TCP
- TCP is reliable because it guarantees the delivery of data to the router of the destination


Answer : The delivery of data to the destination cannot be guaranteed in TCP

Q. Which of the following propositions is not true?

- UDP is faster, simpler and more efficient than TCP
- UDP provides extended error checking mechanisms, because it provides flow control and data acknowledgement
- UDP is a datagram oriented protocol
- UDP supports broadcasting


Answer : UDP provides extended error checking mechanisms, because it provides flow control and data acknowledgement

Q. Which of the following propositions is not true?

- TCP is a datagram oriented protocol
- TCP does not support broadcasting
- TCP provides extended error checking mechanisms, because it provides flow control and data acknowledgement
- Data sequencing is a TCP feature (packets arrive in order in the recipient)
- TCP is reliable because it guarantees the delivery of data to the router of the destination
- TCP is comparatively slower than UDP


Answer : TCP is a datagram oriented protocol

Q. Which of the following services use UDP? 1. DHCP 2. SMTP 3. FTP 4. HTTP

- 3
- 1
- 2
- All of the above


Answer : 1

5. Application Layer

선행지식

5.1. DNS/DHCP 특징

Q. __ translates Internet domain names and host names into IP addresses

- Network time protocol
- Default routing protocol
- Domain name system
- OSI model system


Answer : Domain name system

Q. You want to implement a mechanism that automates IP configuration, including IP address, subnet mask, default gateway and DNS information. What protocol will you use to achieve this?

- SNMP
- DHCP
- SMTP
- ARP


Answer : DHCP

Q. What DHCP protocol does it use at the transport layer level?

- ICMP
- TCP
- FTP
- UDP


Answer : UDP

Q. What type of address is supported by DHCP?

- IPV4
- IPV6
- IPV4 and IPV6
- None of them


Answer : IPV4 and IPV6

Q. DHCP is used for _

- IPV4
- Both IPV6 and IPV4
- IPV6
- None of the mentioned


Answer : Both IPV6 and IPV4
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